Question

if x is equals to 4 + root 15 find the value of x cube minus one upon x cube​

Answer 1

Answer:

Step-by-step explanation:

hence

x=4+ √15

$x^{3}-\frac{1}{x^{3} } =(x-\frac{1}{x})(x^{2} +\frac{1}{x^{2} } +x*\frac{1}{x}  ) =(x-\frac{1}{x})(x^{2} +\frac{1}{x^{2} } +1)$

after substittuting the value you can get value