if x is equals to 5 minus root 21/2 so find x plus one upon x
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Heya !!
X = ( 5 - ✓21 ) / 2
1/X = 2 / ( 5 - ✓21 )
1/X = 2 / ( 5 - ✓21 ) × ( 5 + ✓21 ) / ( 5 + ✓21 )
1/X = 2 ( 5 + ✓21 ) / ( 5 - ✓21 )( 5 + ✓21 )
1/X = 2 ( 5 + ✓21 ) / (5)² - (✓21 )²
1/X = 2 ( 5 + ✓21 ) / 25 - 21
1/X = 2 ( 5 + ✓21 ) 4 = 5 + ✓21 / 2
Therefore,
X + 1/X = ( 5 - ✓21 )/2 + ( 5 + ✓21 )/2
X + 1/X = ( 5 + ✓21 ) + ( 5-✓21) / 2
X + 1/X = ( 5 + 5 /2) = 10/2 = 5
Hence,
X + 1/X = 5.
X = ( 5 - ✓21 ) / 2
1/X = 2 / ( 5 - ✓21 )
1/X = 2 / ( 5 - ✓21 ) × ( 5 + ✓21 ) / ( 5 + ✓21 )
1/X = 2 ( 5 + ✓21 ) / ( 5 - ✓21 )( 5 + ✓21 )
1/X = 2 ( 5 + ✓21 ) / (5)² - (✓21 )²
1/X = 2 ( 5 + ✓21 ) / 25 - 21
1/X = 2 ( 5 + ✓21 ) 4 = 5 + ✓21 / 2
Therefore,
X + 1/X = ( 5 - ✓21 )/2 + ( 5 + ✓21 )/2
X + 1/X = ( 5 + ✓21 ) + ( 5-✓21) / 2
X + 1/X = ( 5 + 5 /2) = 10/2 = 5
Hence,
X + 1/X = 5.
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