Math, asked by sindhu348, 11 months ago

if x is in first quadrant and sinx= cosx,then what is the value of x?​

Answers

Answered by harendrachoubay
1

The value of x is "\dfrac{\pi}{4}".

Step-by-step explanation:

We have,

\sin x = cos x

\sin x = sin( \frac{\pi}{2} - x)

⇒ x = \frac{\pi}{2} - x

⇒ x + x =\dfrac{\pi}{2}

⇒ 2x =\dfrac{\pi}{2}

⇒ x = \dfrac{\pi}{4} or 45°

\dfrac{\pi}{4} lies  in first quadrant.

Hence, the value of x is  "\dfrac{\pi}{4}".

Answered by slicergiza
0

Answer:

The value of x is 45°

Step-by-step explanation:

Given expression,

sin x = cos x

We know that cos a = sin (90 - a)

⇒ sin x = sin (90 - x)

⇒ x = 90 - x

⇒ x + x = 90

⇒ 2x = 90

⇒ x = \frac{90}{2} = 45

Hence, the value of x would be 45°

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