Computer Science, asked by anantkumar69207, 3 months ago

If x is random variable,then var(2-3x) is
1. 2-var(3x)
2. var(2)-var(3x)
3. 2-3var(x)
4. 9var(x)

Answers

Answered by pulakmath007
7

SOLUTION

TO CHOOSE THE CORRECT OPTION

If x is random variable,then var(2-3x) is

1. 2-var(3x)

2. var(2)-var(3x)

3. 2-3var(x)

4. 9var(x)

CONCEPT TO BE IMPLEMENTED

Mean

If X is a random variable corresponding to a random experiment then Arithmetic mean of X denoted by E(X) or by m and defined as m = E(X)

Variance

If X be a random variable corresponding to a random experiment then the variance of X, denoted by Var(X) and defined as

 \sf{Var (X ) = E {(X - m)}^{2}  }

Formula related to Variance

 \sf{Var (aX  + b) =  {a}^{2}  \:   Var (X ) }

EVALUATION

USING FORMULA

 \sf{Var (2 - 3X  ) }

 \sf{ = {( - 3)}^{2}   \:  \: Var (X) }

 \sf{ = 9  \:  \: Var (X) }

NOT USING FORMULA (Using Definition)

Here Mean

= E(2-3X )

= E(2) - 3 E(X)

= 2 - 3m

 \therefore \:  \:  \sf{Var (2 - 3X  ) }

 \sf{ =E{ \{(2 - 3X) - (2 - 3m)  \}}^{2} }

 \sf{ =E{ \{3(X - m)  \}}^{2} }

 \sf{ = {3}^{2} \:  E{ \{(X - m)  \}}^{2} }

 \sf{ = 9  \:  \: Var (X) }

FINAL ANSWER

Hence the correct option is

If x is random variable,then var(2-3x) is

4. 9var(x)

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Answered by Anonymous
2

Answer:

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Explanation:

TO CHOOSE THE CORRECT OPTION

If x is random variable,then var(2-3x) is

1. 2-var(3x)

2. var(2)-var(3x)

3. 2-3var(x)

4. 9var(x)

CONCEPT TO BE IMPLEMENTED

Mean

If X is a random variable corresponding to a random experiment then Arithmetic mean of X denoted by E(X) or by m and defined as m = E(X)

Variance

If X be a random variable corresponding to a random experiment then the variance of X, denoted by Var(X) and defined as

\sf{Var (X ) = E {(X - m)}^{2} }Var(X)=E(X−m)

2

Formula related to Variance

\sf{Var (aX + b) = {a}^{2} \: Var (X ) }Var(aX+b)=a

2

Var(X)

EVALUATION

USING FORMULA

\sf{Var (2 - 3X ) }Var(2−3X)

\sf{ = {( - 3)}^{2} \: \: Var (X) }=(−3)

2

Var(X)

\sf{ = 9 \: \: Var (X) }=9Var(X)

NOT USING FORMULA (Using Definition)

Here Mean

= E(2-3X )

= E(2) - 3 E(X)

= 2 - 3m

\therefore \: \: \sf{Var (2 - 3X ) }∴Var(2−3X)

\sf{ =E{ \{(2 - 3X) - (2 - 3m) \}}^{2} }=E{(2−3X)−(2−3m)}

2

\sf{ =E{ \{3(X - m) \}}^{2} }=E{3(X−m)}

2

\sf{ = {3}^{2} \: E{ \{(X - m) \}}^{2} }=3

2

E{(X−m)}

2

\sf{ = 9 \: \: Var (X) }=9Var(X)

FINAL ANSWER

Hence the correct option is

If x is random variable,then var(2-3x) is

4. 9var(x)

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