Question

If x is real, prove that 5x^2 - 8x + 6 is always positive and find its minimum value.​

Answer 1

Answer:14/5

Step-by-step explanation:

By differentiating wrt x, u get minima when

=10x-8=0, x=4/5.

Substituting back in eqn,

Minima=5.(4/5)²-8.4/5+6

=14/5.

So all values of the equation should be e more than 14 by 5 and hence it is always positive.