if x is real prove that x/x'2-5x+9 lies on -1/11 & 1
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Answer:
let
x
2
−5x+9
x
=y
x=yx
2
−(5y)x+9y
yx
2
−(1+5y)x+9y
For this quadratic equation to have real roots
Discriminant must be ≥0
(−1−5y)
2
−4×y×9y≥0
1+25y
2
+10y−36y
2
≥0
1+10y−11y
2
≥0
1−y+11y−11y
2
≥0
(1−y)+11y(1−y)≥0
(11y+1)(y−1)≤0
So (y−(
11
−1
))(y−1)≤0
So y∈[ 11−1 ,1]
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