Question

If x is real, prove thatx÷x2-5x+9 lies between -1÷11and 1
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Answer 1

Answer:

Put 62 = a2 — 02 and hence b2 22 + azy2 : 02 b2 ( 11) x2 y2 01' a_2 + 5? = l. (12) This is ... Therefore every point X of the said locus lies on the ellipse (12 ). ... From (12) we mount up to (11) and then (10).

Step-by-step explanation:

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