If x is real the maximum value of 3x^2+9x+17/3x^2+9x+7 is
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Answered by
3
By taking limit as x tends to infinity
Direct is considered constant terms
Direct is considered constant terms
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Answered by
1
Answer:
41
Step-by-step explanation:
f(x)=
3x
2
+9x+7
3x
2
+9x+17
=
3x
2
+9x+7
3x
2
+9x+7+10
=1+
3x
2
+9x+7
10
f
′
(x)=0 for maximum value
f
′
(x)=
(3x
2
+9x+7)
2
10(6x+9)
6x+9=0
x=−
2
3
As x is real so maximum value is f(x)=1+
3(−
2
3
)
2
+9(−
2
3
)
2
+7
10
=1+
4
24
−
2
27
+7
10
=1+
4
27−54+28
10
=1+
1
40
=41
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