Math, asked by abinandmidhun243, 11 months ago

If x is real, the maximum value of \frac{3x^2+9x+17}{3x^2+9x+7} is
(a) \frac{1}{4}
(b) 41
(c) 1
(d) \frac{17}{7}

Answers

Answered by brunoconti
0

Answer:

Step-by-step explanation:

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