If x is real what will not be the value of the expression x^2+2x-3/x^2+2x-8
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x^2+2x-3/x^2+2x-8
x^2-x+3x-3/x^2+4x-2x-8
x(x-1)+3(x-1)/x(x+4)-2(x+4)
(x-1)(x+3)/(x+4)(x-2)
For x to be real,denominator must not zero.
i.e x should not be equal to 2, -4
x^2-x+3x-3/x^2+4x-2x-8
x(x-1)+3(x-1)/x(x+4)-2(x+4)
(x-1)(x+3)/(x+4)(x-2)
For x to be real,denominator must not zero.
i.e x should not be equal to 2, -4
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1
Answer:
1. Let for some y which is equal to the given expression for all real values of x.
2. Then u will get a quadratic in x which is x^2(1-y)+2x(1-y)-3+8y=0
3. Then apply the cases for D greater than equals 0 and 1-y should not be equal to zero. And then solve.
4. Proceed and u will get the answer.
5. It is a multi correct. Answer would be c and d.
6. Don't mind there may be some calculations error.
Thanks, best of luck...
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