If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18, what is the average of x, y, and z in terms of m?
A) m+6
B) m+7
C) 2m+14
D) 3m+21
Answers
Answered by
0
ANSWER EXPLANATION: Since the average (arithmetic mean) of two numbers is equal to the sum of the two numbers divided by 2, the equations x=m+92, y=2m+152, z=3m+182are true. The average of x, y, and z is given by x+y+z3. Substituting the expressions in m for each variable (x, y, z) gives
[m+92+2m+152+3m+182]3
This fraction can be simplified to m+7.
The final answer is B.
Answered by
0
Answer:
ANS IS B
Step-by-step explanation:
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