Question

If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18, what is the average of x, y, and z in terms of m?
A) m+6
B) m+7
C) 2m+14
D) 3m+21

Please give me right answer and if you dont know the answer then dont give pls.

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Answer 1

Answer:

If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18, what is the average of x, y, and z in terms of m?

Step-by-step explanation:

Since x is the average of m and 9, we get

x = (m + 9)/2

Similarly,

y = (2m + 15)/2

and z = (3m + 18)/2

Average of x, y and z would be

(x + y + z)/3

Now, put x, y and z in terms of m

Putting value of x ,y & z from Equation (1), (2) & (3),

➻[ (m + 9)/2 + (2m+15)/2 + (3m+18)/3 ]

➻ [ (m + 9 + 2m + 15 + 3m + 18) / 3 ]

➻ [ (6m + 42) /2*3 ]

➻ [6 (m + 7) /6 ]

➻ [ (m + 7) ]

Hence, the average of x, y and z is (m + 7)

(m + 7) (Option B). (Ans).

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Answer 2

option c 2m + 14 is correct answer I am Poonam