Math, asked by Anonymous, 4 months ago

If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18, what is the average of x, y, and z in terms of m?​

Answers

Answered by tanmaykumarsingh786
0

Answer:

Given, x=

2

m+9

y=

2

2m+15

z=

2

3m+18

Average of x,y,z=

3

2

m+9

+

2

2m+15

+

2

3m+18

=

3

2

6m+42

=m+7

Answered by UniqueBabe
5

Answer:

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pls thanks mat dijiya

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