If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18, what is the average of x, y, and z in terms of m?
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Answered by
1
Answer:
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Step-by-step explanation:
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Answered by
1
Step-by-step explanation:
Given, x=
2
m+9
y=
2
2m+15
z=
2
3m+18
Average of x,y,z=
3
2
m+9
+
2
2m+15
+
2
3m+18
=
3
2
6m+42
=m+7
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