If x is the mean of x₁,x₂............xⁿ and y is the mean of y₁, y₂,…….yn and z is the mean of x₁,x₂............xn , y₁, y₂,……….yⁿ then z =? Write the correct alternative answer for the question.
(A)x +y/2
(B)x+y
(C)x+y/n
(D)x+y/2n
Answers
Answered by
1
Given ,
x is the mean of x1 , x2 , ... , xn
Sum of n observations of x = xn ...(1)
y is the mean of y1 , y2 ,........., yn
Sum of n observations of y = yn .
Now ,Z is the mean of all observations of x ,y .
We know that ,
Mean = Sum of observations / Number of observations .
So ,
Z = nx + ny / ( n + n )
Z = n ( x + y ) / 2n
Z = x + y /2 .
Therefore ,The correct relation is Z = x + y /2 .
Ans : Option A
x is the mean of x1 , x2 , ... , xn
Sum of n observations of x = xn ...(1)
y is the mean of y1 , y2 ,........., yn
Sum of n observations of y = yn .
Now ,Z is the mean of all observations of x ,y .
We know that ,
Mean = Sum of observations / Number of observations .
So ,
Z = nx + ny / ( n + n )
Z = n ( x + y ) / 2n
Z = x + y /2 .
Therefore ,The correct relation is Z = x + y /2 .
Ans : Option A
Answered by
2
Option ( A ) is correct.
Explanation :
Given , mean of xn terms = x
Mean if y1,y2 , ...,yn = y
Therefore ,
z = ( x + y )/2
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