if x is the mean of x₁ , x₂ , ...... xₙ. prove that Σ( xi - x = 0)
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YᎾᏌᎡ ᏚᎾᏞᏌᎢᏆᎾN -:
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Given :-
Mean of x1 , x2 , ....... xn..numbers is 'x'.
Prove -:
Σxi - x = 0
We know that,
Mean = sum of observations / number of observations.
x = x1 + x2 +..... xn / n
On cross multiplying,
nx = x1 + x2 +.... xn
Now,
= nΣxi - x = (x1 - x) + (x2 - x) +.......(xn - x)
= (x1 + x2 +......xn) - nx
= nx - nx
= 0
So, ∑xi - x= 0
_____________________________
Given :-
Mean of x1 , x2 , ....... xn..numbers is 'x'.
Prove -:
Σxi - x = 0
We know that,
Mean = sum of observations / number of observations.
x = x1 + x2 +..... xn / n
On cross multiplying,
nx = x1 + x2 +.... xn
Now,
= nΣxi - x = (x1 - x) + (x2 - x) +.......(xn - x)
= (x1 + x2 +......xn) - nx
= nx - nx
= 0
So, ∑xi - x= 0
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