Question

If x=¾ is the root of the polynomial f(x) = 6x ^ 3 - 11x ^ 2 + kx - 20 Then find the value of k.​

Answer 1

Answer:

 k = 31.533

Step-by-step explanation:

f(x) = 6x ^ 3 - 11x ^ 2 + kx - 20

x = 3/4

so f[3/4] = 6[3/4]^3 - 11[3/4]^2+k[3/4] -20

         0 = 2.53 - 6.18 + 0.75k - 20

         k = 31.533