if x is the smallest three digit number which when divided by 5 leaves a remainder 3 and y=6x+5,then how many minimum integers that can be inserted between x and y ( with proper explanation)
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Answer:
The number when divided by 6 should give a remainder as 5. I can therefore write the number as 6x + 5 where x is the quotient when the number is divided by 6 and 5 is the remainder. Similarly when divided by 5 should give a remainder as 3. the same number can also be written as 5y + 3 where y is the quotient when the number is divided by 5 and the remainder is 3.
Since the number is same we can equate it as 6x+ 5 = 5y +3 or 6x = 5y-2 since x and y are quotients it cant be in fractions the smallest value of y that can satisfy the equation is 4 and y will be 3
When we sustitute 3 and 4 for x and y respetively in the term 6x+ 5 or 5y+ 3 you will get the term as 23. the least value satisfying the question is 23 but the question mentions about largest three digit number.
Answer:
this is the answer of your question
