Question

If x-iy=2-3i/2+3i . prove that: x2 + y2 = 1.

Answer 1

Answer:

x2 + y2 = 1

proved

LHS = RHS

Answer 2

Answer:

x^2+y^2=1

Step-by-step explanation:

x-iy=2-3i/2+3i

as |x+iy|=√x^2+y^2

so by applying both sides,we get

|x+iy| = |2-3i|/|2+3i|

or, √x^2+y^2 = √2^2+3^2/√2^2+3^2

or, √x^2+y^2 =1

or,x^2+y^2 = 1^2

:- x^2+y^2 = 1 proved