Question

If (x +iy)/3 = a +ib , then х у + a b -- (a) 4(x2 + y) (c) 4(a? - 62) (b) 4(b? - a?) (d) 4(a? + b3)​

Answer 1

Answer:

(x+iy)=(a+ib)3

a3+(ib)3+3abi(a+ib)

x+iy=a3−ib3+3a2bi−3ab2

∴x=a3−3ab2 ,y=−b3+3a2b

⇒ax=a2−3b2 ,by=−b2+3a2

so,ax+by=4a2−4b2

=4(a2−b2)

Answer 2

Answer:

4(a2-b2)

Step-by-step explanation:

nothing is there a