if X+iy^a=alfa^alfa+ beta
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Given x = a+b, y = aα +bβ and z = aβ+bα
α,β are cube roots of unity.
So α = ω, β = ω2
xyz = (a+b)(aα +bβ)( aβ+bα)
= (a+b)(a2αβ+abα2+abβ2+b2αβ)
= (a+b)(a2αβ+ab(α2+β2)+b2αβ)
Substitute α and β in above equation
= (a+b)(a2(ωω2)+ab(ω2+ω4)+b2(ωω2))
= (a+b)(a2-ab+b2)
= a3+b3
Hence option (3) is the answer.
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