Question

if x=k is one of the solution of 2x^2+5x-k=0, find the two possible value of k

Answer 1

p(k)=2k^2 + 5k - k = 0

= 2k^2 + 4k = 0

=2k(k + 2) = 0

therefore,

2k = o and k = o

or

k + 2 = 0 and k=-2

Answer 2

the possible values for k are k = 0 or k = 2