Question

if x=k root 2 then the solution of the quadratic x^2+root 2x-4 =0
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Answer 1

Answer:

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Answer 2

Step-by-step explanation:

x² + √2x - 4 = 0

→ 2k² + 2k - 4 = 0 [ as, x = k√2 ]

→ k² + k - 2 = 0 [ both side are divided by 2 ]

→ k² - 1 + k - 1 = 0

→ (k+1) (k-1) + 1(k-1) = 0

→ (k-1) (k+1+1) = 0

→ (k-1) (k-2) = 0

→ (k-1) = 0 or (k-2) = 0

→ k = 1 or k = 2

so,

k = 1, 2

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