If x=k square y=k is solution of x-5y+6=0 find k
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32
- x = k²
- y = k
x - 5y + 6 = 0
___________ [GIVEN]
We have to find the value of k.
______________________________
x - 5y + 6 = 0
» Put x = k² and y = k in above equation
=> k² - 5k + 6 = 0
=> k² - 3k - 2k + 6 = 0
=> k(k - 3) - 2(k - 3) = 0
=> (k - 2) (k - 3) = 0
• k - 2 = 0
=> k = 2
• k - 3 = 0
=> k = 3
_____________________________
k = 2 and 3
_________ [ANSWER]
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