Question

if x =k² and y =k is a solution for x-3y =10 find the value of k​

Answer 1

Answer:

if x=k2

then, k^2-3k=10

k(k-3)=10

k=10. or k=10+3=13

Answer 2

Put the given values in the equation

K^2-3k-10= 0

K^2 -5k+2k-10= 0

K(k-5) + 2(k-5) =0

(K+2)(k-5) = 0

Therefore, k = -2,5