Question

If x = k2 and y = k is a solution of the equation x – 7y + 12 = 0, find the value of k.

Answer 1

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→ putting x and y

$\small k2−5k+6=0 \\ ⇒k2−3k−2k+6=0 \\ ⇒k(k−3)−2(k−3)=0 \\ ⇒(k−2)(k−3)=0 \\ ⇒k=2 or k=3$

• K = 2

• K = 3

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Answer 2

Answer:

k=4,3

Step-by-step explanation:

k²-7k+12=0

k²-4k-3k+12=0

k(k-4)-3(k-4)=0

(k-4)(k-3)=0

(k-4)=0 or (k-3)=0

k=4 or k=3