Question

If x = k2 and y = k is the solution of the equation x − 3y = 10, find value of k.​

Answer 1

It is given that x = $k^{2}$ and y = k

The equation given is x - 3y = 10

Let us replace the value of x and y :

$k^{2} -3k=10$

$k^2-3k-10=0$

$k^2-5k+2k-10=0$

$k(k-5)+2(k-5)=0$

$(k-5)(k+2)=0$

So k = 5 or k = -2

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