Question

If x = log, 3, y = log, 11, then
a) x=y
b) x <y
c) x>y
d) x = 3y
​

Answer 1

Answer:

C) x<y

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Step-by-step explanation:

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Answer 2

$x = log(3) \: \: \: \: and \: \: \: \: y = log(11) \\ \\ solution = \\ \\ adding\: \: both \: \: the \: \: terms \\ \\ \\ x + y = log(3) + log(11) \\ \\ x + y = log(3 \times 11) ......... log(m) + log(n) = log(mn) \\ \\ x + y = log(33).............(1) \\ \\ now \: \: subtracting \\ \\ x - y = log(3) - log(11) \\ \\ x - y = log( \frac{3}{11} ) \\ \\ x = y + log( \frac{3}{11} ).............(2) \\ \\ or \\ \\ y = x + log( \frac{11}{3} ) ........(3) \\ \\ \\ since \: \: \: \: \: log(10) = 0 \\ \\ \\ hence \\ \\ from \: \: 1.2.3 \\ \\ x < y$