Question

If x= log 4/5, y = log 3/5 and z= 2log √3/2 find:
i) x-y+z
ii) 4x-y+z

Answer 1

solution

given x=log4/5

y=log3/5

2z=log√3/2

to find x-y+z

=log4/5-log3/5+2log√3/2

=log4/5-log3/5+log(√3/2)²

=log4/5-log3/5+log3/2

=log4/5*3/2-log3/5

=log12/10-log3/5

=log(12/10/3/5)

=log(12/10*5/3)

=log(4/2)

=log2

Answer 2

Ello❤❤

Here is ur answer !
-------------------------------------------------------------------

$1. \: x - y + z \: = \: log \frac{4}{5} - log \frac{3}{5} = 2log \frac{ \sqrt{3} }{2} \\ = log \frac{4}{5} - log \frac{3}{5} + (log { \frac{ \sqrt{3} }{2} })^{2} \\ \\ = log (\frac{4}{5} \div \frac{3}{5} \times \frac{3}{5} ) \\ \\ = log( \frac{4}{5} \times \frac{5}{3} \times \frac{3}{4} ) \\ \\ = log1 \: = 0 \\ \\ 2) {4}^{x - y + z} = {4}^{0} = 1$

____________________
❤Be brainly❤
# cutecmsian