If x= log (a-b),y=log (a^2+ab+b^2), and z=log(a+b) find the relationship between x,y and z
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Relationship between x,y,z is z = x + y
Step-by-step explanation:
Given :
- x = log ( a - b)
- y = log ( a² + ab + b² )
Look like z = log ( a³ - b³ )
=> z = log ( a³ - b³ )
Using identity a³ - b³ = ( a - b) ( a² + ab + b²)
=> z = log [ (a + b)( a² + ab + b² ) ]
Using Product rule log pq = log p + log q
=> z = log (a - b) + log( a² + ab + b² )
=> z = x + y
Hence the relation is z = x + y
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