if x=log [a-b]; y=log [a+b] ; z= log [a2 - b2 ] then write the relationship between x,y,z
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Answered by
6
Answer:
please refer the attachment for procedure
Attachments:
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Answered by
2
z = x + y , if x=log(a+b) y=log(a-b) z=log(a²-b²)
Step-by-step explanation:
x=log(a+b)
y=log(a-b)
z=log(a²-b²)
z = log(a²-b²)
=> z = log ( (a + b)(a - b) )
as we know that log(xy) = logx + logy
x = a + b & y = a - b)
=> z = log(a + b) + log(a - b)
=> z = x + y
z = x + y , if x=log(a+b) y=log(a-b) z=log(a²-b²)
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