If x=log3base2 and Y=log5base2 then find log7.5base2 and log60base2
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Answer:
Now, log
140
63=log
2
2
×5×7
(3×3×7)
=
log
2
(2
2
×5×7)
log
2
(3×3×7)
=
2log
2
2+log
2
5+log
2
7
log
2
3+log
2
3+log
2
7
=
2+b+
c
1
2a+
c
1
=
2c+bc+1
2ac+1
.
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