Question

If |x|<1, y = x-x^2+x^3-x^4+.......
infinity then find the value of x in terms of y.​

Answer 1

Answer:

Step-by-step explanation:

x value is 2ans y vakue is 5

Answer 2

Step-by-step explanation:

ANSWER

The R.H.S. of the equation is a sequence in geometric progression with infinite terms, with,

first term, i.e., a = x, and

common ratio, i.e., r = -x

Now, sum of a sequence in geometric progression with infinite terms is given by

S = a/(1-r)

Here, x∈(-1, 1], otherwise the sum of the terms will be infinite.

Therefore,

R.H.S. = x/(1+x)

Now, y = x/(1+x)

⇒ y+xy = x

⇒ y = x(1-y)

⇒ x = y/(1-y) = answer