Question

If x=m is one of the Solutions of the equation
2x^2 +5x-m=0 the possible values of m are .​

Answer 1

Answer:

ContourPlot[{-m + x (5 + 2 x) == 0, x == m}, {m, -3.90625, 2.}, {x, -2.83745, 2.}]

Step-by-step explanation:

{m = 2 x^2 + 5 x, x = m}

m = -2, x = -2

M=0,X=0

Answer 2

Answer:

given

2x²+5m -m= 0

m= x

to find

possible values of m

solution

substitute the value of m as x in 2x²+5m -m= 0

2x²+5x-x = 0

2x²+4x= 0

2x²= - 4x

x= -2

so the possible value of m is -2 for 2x²+5m -m= 0