Question

If x=m is one solution of equation 2x^2+5x-m=0 then possible values of m

Answer 1

Answer:

m = -2

Step-by-step explanation:

x = m

2x^2 + 5x - x = 0

2x^2 + 4x = 0

2x^2 = -4x

x = -2

Answer 2

The value of m is $m=0,-2$.

Step-by-step explanation:

Given : If x=m is one solution of equation $2x^2+5x-m=0$.

To find : The values of m ?

Solution :

The equation $2x^2+5x-m=0$.

Substitute x=m,

$2m^2+5m-m=0$

$2m^2+4m=0$

$2m(m+2)=0$

$2m=0,(m+2)=0$

$m=0,m=-2$

Therefore, the value of m is $m=0,-2$.

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