Question

If x=[√(m+n) + √(m+n)]÷[√(m+n) - √(m+n)]
Then find value of nx^2 - 2mx + n

Answer 1

Answer:If x = square root of (m+n)+square root of (m-n)/square root of (m+n)-square root (m-n), where n which isn't equal 0 , then find the value of nx^2 - 2mx + n.

squaring both sides

(nx-m)² = m² - n²

=> n²x² + m² - 2mnx = m² - n²

=> n²x² - 2mnx = - n²

Diving by n both sides

=> nx² - 2mx = - n

=> nx² - 2mx + n = 0

Step-by-step explanation: