If x = √(m+n) + √(m-n)/√(m+n) - √(m-n) then nx^2-2mx+n
Answers
Answered by
3
Theanswerisgivenbelow:Now,x=m+n−m−nm+n+m−nWerationalizethedenominatorbymultiplyingboththenumeratoranddenominatorby(m+n+m−n).So,x=(m+n−m−n)(m+n+m−n)(m+n+m−n)(m+n+m−n)=(m+n)−(m−n)(m+n)+2(m+n)(m−n)+(m−n)=2n2m+2m2−n2=nm+m2−n2Or,nx=m+m2−n2Or,nx−m=m2−n2Now,squaringbothsides,weget(nx−m)2=(m2−n2)2Or,n2x2−2mnx+m2=m2−n2Or,n2x2−2mnx=−n2Or,nx2−2mx=−n
Or,nx2−2mx+n=0Hence
nx2−2mx+n=0(Answer)
Or,nx2−2mx+n=0Hence
nx2−2mx+n=0(Answer)
Answered by
1
Answer:
Hope this helped you.
Thank you.
Attachments:
Similar questions