Question

If x^m = y^n = z^q; xyz=1 and m not equals to 0 find 1/m + 1/n + 1/p

please answer fast with proper explanation​

Answer 1

Given : x^m = y^n = z^p;  

xyz=1

To Find :   1/m + 1/n + 1/p

Solution:

 x^m = y^n = z^p = k

x = k ^(1/m)

y = k ^(1/n)

z = k (1/p)

xyz = k ^(1/m + 1/n + 1/p)

=> 1 = k ^(1/m + 1/n + 1/p)

=> 1/m + 1/n + 1/p = 0

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