Question

if x minus 1 is equal to a, then prove that 2 cube A cube + 8 is equal to 8 x cube minus 16 X square + 16 x minus 8ax
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Answer 1

Step-by-step explanation:

2^3a^3+8=8x^3_16x^2+16x-8ax

LHS

8(x-1)^3+8 a=x-1 given

8[(x^3-1^3-3x1(x-1)]+8 (a-b)^3 formula

8x^3-8-24x^2+24x+8

=8x^3-24x^2+24x

RHS

8x^3-16x^2+16x-8(x-1)x

8x^3-16x^2+16x-8x^2+8x

=8x^3-24x^2+24x

so LHS=RHS

hence proved

hope it helps