Question

if x minus 1 upon x = 25 find the value of x to the power 4 + 1 upon x to the power 4​

Answer 1

Answer:

$x-\dfrac{1}{x} = 25$

Squaring both sides,

$(x-\dfrac{1}{x})^2 = 25^2$

$x^2-2+\dfrac{1}{x^2} = 625$

$x^2+\dfrac{1}{x^2} = 627$

Squaring both sides again,

$(x^2+\dfrac{1}{x^2})^2 = 627^2$

$x^4+2+\dfrac{1}{x^4} = 393129$

$\bold{x^4+\dfrac{1}{x^4} = 393127}$