if x minus 1 whole cube is equal to 8 find X + 1 whole square
Answers
Answered by
153
(x-1)^3 = 8
(x-1)^3 =(2)^3
![(x - 1) = { \sqrt[3]{2} }^{3}](https://tex.z-dn.net/?f=%28x+-+1%29+%3D+%7B+%5Csqrt%5B3%5D%7B2%7D+%7D%5E%7B3%7D+ "(x - 1) = { \sqrt[3]{2} }^{3}")
x-1 = 2
x=2+1 =3
x=3
(x+1)^2
= (3+1)^2= 4^2
=4×4
=16 answer
hope this helps you
plzzzzz mark as brainliest answer plzzzzz
(x-1)^3 =(2)^3
x-1 = 2
x=2+1 =3
x=3
(x+1)^2
= (3+1)^2= 4^2
=4×4
=16 answer
hope this helps you
plzzzzz mark as brainliest answer plzzzzz
shreyabambal:
I asked whole square not whole cube but I understood the problem. Thanks
plzzzzz now mark my answer as brainliest answer plzzzzz
i have correct my mistake
Answered by
16
( x-1)*(x-1)*(x-1)=8 then x-1=2 and x=3 so value of( x+1)*(x+1)=(3+1)*(3+1)= 16
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