if x minus 2 is a factor of 2 x cube minus 7 x square + 11 x + 5a find value of a
smily1439:
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Answered by
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By factor theorem,
If x-2 is factor of p(x) = 2x^3 - 7x^2 + 11x + 5a then p(a) = 0.
Hence p(2) = 0
=) 2x^3 - 7x^2 + 11x + 5a = 0
=) 2(2)^3 - 7(2)^2 + 11(2) + 5a = 0
=) 16 - 28 + 22 + 5a = 0
=) 10 + 5a = 0
=) 5a = - 10
=) a = - 10/5
=) a = - 2.
Hope it's helpful to u.
If x-2 is factor of p(x) = 2x^3 - 7x^2 + 11x + 5a then p(a) = 0.
Hence p(2) = 0
=) 2x^3 - 7x^2 + 11x + 5a = 0
=) 2(2)^3 - 7(2)^2 + 11(2) + 5a = 0
=) 16 - 28 + 22 + 5a = 0
=) 10 + 5a = 0
=) 5a = - 10
=) a = - 10/5
=) a = - 2.
Hope it's helpful to u.
hmmm
so according to ur question a is 2 so p(a) =0
ya i understood thanku
p(a) means to place value of a which is equal to 2 in every place of x
mention nott
ha i understood
oohk
hey
1 thng
hm tel
Answered by
2
Answer: a = -2
Step by step explanation:
BY FACTOR THEOREM
If x-2 is a factor of p(X) then p(a) = 0
hence p(2)=0
so,
=> 2x^3-7x^2+11x+5a=0
=> 2×2^3-7×2^2+11×2+5a=0
=> 16-28+22+5a=0
=> 10+5a=0
=> 5a=-10
=> a= -10÷5
=> a= -2
THE CORRECT ANSWER
HOPE IT HELPED YOU
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