if x minus 2 is a factor of x cube + x square + bx + 16 and b is equal to 4 find the value of a and b
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Given,
x-2 is a factor of x³+ax²+bx+16
⇒2 is the zero of polynomial p(x)=x³+ax²+bx+16
⇒p(2)=(2)³+a(2)²+b(2)+16
⇒0=8+4a+2b+16
Given,b=4a
⇒0=8+4a+2(4a)+16
⇒0=8+12a+16
⇒12a= -24
⇒a=(-24)/12
⇒a= -2
b=4a
⇒b=4(-2)
⇒b= -8
Value of a is -2 and b is -8.
mysticd:
b = 4 not 4a
plz , check once
Sir there's error in question
If it would have given the value of b=4, then why it is asked to find value of both a and b
b is already given , we have to find a
But in question, there is need to find a and b. That's why i took b = 4a
See the question once, there is no a given.
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Answered by
2
Hey mate we have given the value of b=4 but where is a in the whole statement .
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