Math, asked by ayushkumar04, 11 months ago

if x minus 2 root 6 into 5 root 3 + 5 root 2 by 5 root 3 minus 5 root 2 is equals to 1 then find the value of x​

Answers

Answered by rushikesh11111111
2

 \frac{x - 2 \sqrt{6 } -5 \sqrt{3} -   5 \sqrt{2}  }{5 \sqrt{3} - 5 \sqrt{2}  }  = 1 \\ x - 2 \sqrt{6} - 5 \sqrt{3} -5 \sqrt{2} = 5 \sqrt{3} - 5 \sqrt{2} \\ x - 2 \sqrt{6} - 5 \sqrt{3} = 5 \sqrt{3} \\ x - 2 \sqrt{6} = 10 \sqrt{3} \\ x = 2(5 \sqrt{3} +  \sqrt{6}) \\


ayushkumar04: thank you
ayushkumar04: but the question is (x-2√6)(5√3+5√2) / 5√3-5√2=1
rushikesh11111111: okay
rushikesh11111111: sorry
rushikesh11111111: I miss understood the question
Answered by ajim12
3

Answer:

So, the answer is 5 ......hope u will like this...I am not sure about the answer

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