Math, asked by Archyanwar6383, 10 months ago

if x minus one by x =3 evaluate x cube minus one by x cube

Answers

Answered by manu26032006
1

Answer:

I guess it will help you

Attachments:
Answered by tejasgupta
5

Answer:

36

Step-by-step explanation:

x - \dfrac{1}{x} = 3\\\\\\\text{Cubing both sides, we have,}\\\\\\\left( x - \dfrac{1}{x} \right) ^3 = 3^3\\\\\\\implies x^3 - \dfrac{1}{x^3} - 3(x) \left( \dfrac{1}{x} \right) \left( x - \dfrac{1}{x} \right) = 27\\\\\\\implies x^3 - \dfrac{1}{x^3} - 3(3) = 27\\\\\\\implies \boxed{x^2 - \dfrac{1}{x^3} = 27  + 9 = \boxed{\bold{36}}}

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