Question

if x minus one by X equal to 9 find the value of x square + 1 by x square​

Answer 1

$x - \frac{1}{x } = 9$

${x - \frac{1}{x}}^{2} = {9}^{2}$

${x}^{2} -{ \frac{1}{x}}^{2} = 81 + 2 \\ {x}^{2} - \frac{1}{x} { =}^{2} = 83$

so using identities we will solve

(a-b)²=a²+b²-2ab

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