Question

If x minus one upon X is equals to minus 1 find the value of x squared plus one upon x square

Answer 1

Hey friend,
Here is the answer you were looking for:

Identities used :

${(a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab$


Now,
Given that,

$x - \frac{1}{x} = - 1$


Squaring both the sides we get,

${(x - \frac{1}{x}) }^{2} = {( - 1)}^{2} \\ \\ {x}^{2} + ( \frac{1}{x} )^{2} - 2 \times x \times \frac{1}{x} = - 1 \times - 1 \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } - 2 = 1 \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } = 1 + 2 \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } = 3$

Hope this helps!!

If you have any doubt regarding to my answer, feel free to ask in the comment section or inbox me if needed.

@Mahak24

Thanks...
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