if x minus y = 6 and xy = 20 find the value of x cube minus y cube
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Answer:
the question is wrong that can't happen
if it is x-y=8 then x=10,y=2
Step-by-step explanation:
x-y=8
(10)-(2)=8 [x=10,y=2]
10-2=8
8=8
LHS=RHS
xy=20
10*2=20 [x=10,y=2]
20=20
LHS=RHS
x^3-y^3
(10)^3-(2)^3
1000-8
Answer= 992
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