if x molal of a compoumd in benzene has mole fraction of solute equal to .4 then the value of x is
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Molality = Moles of solute / Weight of Solvent in kg
x = n / 1000
n = 10000x
Mole fraction of solute given is 0.4
0.4 = 1000x / (1000x + 1000/78)
0.4 = 1000x / (1000x + 12.82)
5.128 + 400x = 1000x
x = 117.0 m
Value of x is 117.0 m
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x = n / 1000
n = 10000x
Mole fraction of solute given is 0.4
0.4 = 1000x / (1000x + 1000/78)
0.4 = 1000x / (1000x + 12.82)
5.128 + 400x = 1000x
x = 117.0 m
Value of x is 117.0 m
Please mark it brainliest.
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Answer:
correct answeris 3.2
Explanation:
X molal means X moles in 1kg benzene. Mole fraction of solute
=X+781000X=0.2
X+12.82X=0.2
X=0.2X+(12.82×0.2)=3.2
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