If x molal solution of a compound in benzene has mole fraction of solute equal to 0.4 then the value of x is
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x=8.6 molal solution
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Explanation:
Basis - 1000 g of benzene
Mole fraction =moles of x/moles x+ moles of y
no.of moles of benzene =1000g/78=13moles
y= benzene
(X)Mole fraction =No.of moles of x /No.of moles of benzene +no.of moles of x
0.4=x/x+13
0.4(x+13)=x
0.4x+5.2=x
5.2=0.6x
5.2/0.6=x
x=8.666666666666666666
x=8.6moles
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